A 55 MWe hydroelectric generating station produced 158 GW hr of electricity during the first eight monthf 2017and then was shut down for the rest of the year. Compute the plant …

Question

asked Nov 14, 2020 139k views

1 Answer

Tibortru · Answer 1 · 2020-11-20T13:18:32+0000

Answer:

plant capacity factor = 4.82

Step-by-step explanation:

given data:

total production of electricity = 158GW = 158*10³ MWhr

capacity of the plant = 55MW

Total time period (8 month )= 8*30*24 hr

plant capacity factor =
(actual energy generated(MWh))/(capacity of plant(MW) * time period (h))

plant capacity factor =
(153*10^(3)(MWh))/(55(MW) * 8*30*24 (h))

plant capacity factor = 4.82