Question

A flexible container at an initial volume of 6.13 L contains 8.51 mol of gas. More gas is then added to the container until it reaches a final volume of 18.5 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answer 1

Step-by-step explanation:

According to Avogadro's law, equal volumes of all the gases at same temperature and pressure will also, have same number of molecules.

That is,
`V \propto n`

or
`(V)/(n)` = k

Since, it is given that
`V_(1)` is 6.13 L,
`n_(1)` is 8.51 mol, and
`V_(2)` is 18.5 L.

Hence, calculate the
`n_(2)` as follows.

`(V_(1))/(n_(1)) = (V_(2))/(n_(2))`

`(6.13 L)/(8.51 mol) = (18.5 L)/(n_(2))`

`{n_(2)}` = 0.35 mol

Thus, we can conclude that the number of moles of gas added to the container is 0.35 mol.