Question

A container contains 12 diesel engines. The company chooses 5 engines at​ random, and will not ship the container if any of the engines chosen are defective. Find the probability that a container will be shipped even though it contains 2 defectives if the sample size is 5.

Answer 1

Answer:
`(^(10)C_5)/(^(12)C_5)`

Explanation:

Given a total of 12 diesel engines

out of which 2 are defective

Company have to choose 5 good engines to ship.

Therefore no of ways in good engines are selected is
`^(10)C_5`

no of ways in which any 5 engines are selected from a total of 12 engines is

`^(12)C_5`

Therefore the required probability =
`(^(10)C_5)/(^(12)C_5)`

=
`(7)/(22)`=0.318