Question

Two long parallel wires each carry a current of 5.0 A directed to the east. The two wires are separated by 8.0 cm. What is the magnitude of the magnetic field at a point that is 5.0 cm from each of the wires

Answer 1

24μT

Step-by-step explanation:

According to the question the horizontzal component of the field at P are equal and opposite therefore, it will get cancelled.

And vertical components will be added

So, net magnetic field will be
`B_(net)`

`B_(net)`= 2Bsinθ

`B=(\mu _(0)I)/(2\pi*5*10^(-2))=(2*10^(-7)*5)/(5*10^(-2))`

`B=2*10^(-5)T`

therefore,
`B_(net)`=
`2*2*10^(-5)* [\tex][tex](3)/(5)` ( sinθ=3/5)

on calculating we get
`B_(net)`= 24μT