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Find the value of x in a triangle with one side 11 and 1 angle being 28​

Find the value of x in a triangle with one side 11 and 1 angle being 28​-example-1

2 Answers

2 votes

Answer:

C: 12.5

Explanation:

The sides x and 11 could be defined as the Adjacent angle and the Hypotenuse. This means that we will use the cos function to solve this.

First we can set up our equation


cos28=(11)/(x)

Next we can solve for x by multiplying by x and dividing by
cos 28


x=(11)/(cos28)\\\\x=12.458\\\\x=12.5

answered
User Akawhy
by
7.7k points
3 votes

Answer:

c 12.5

Explanation:

cos 28 = adjacent side/ hypotenuse

cos 28 = 11/x

Multiply each side by x

x cos 28 = 11/x *x

x cos 28 = 11

Divide each side by cos 28

x cos 28/ cos 28 =11 /cos 28

x = 11 /cos 28

x =12.45827056

To the nearest tenth

x = 12.5

answered
User Dark
by
7.9k points

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