Question

A car travels at a constant speed around a circular track whose radius is 3.27 km. The car goes once around the track in 380 s. What is the magnitude of the centripetal acceleration of the car?

Answer 1

The magnitude of the centripetal acceleration of the car is 0.22 m/s².

Step-by-step explanation:

t= 380 sec

r= 3.27km= 3270m

d=π*r=π*3270m

d= 10273m

d=Vt*t

Vt= d/t = 10273m/380s

Vt= 27.03 m/s

ac= Vt²/r

ac= (27.03 m/s)²/3270m

ac=0.22 m/s²