Question

A sled with a mass of 20 kg slides along frictionless ice at 4.5 m/s. It then crosses a rough patch of snow that exerts a friction force of 12 N. How far does it slide on the snow before coming to rest?

Answer 1

Answer:The sled slides 16.875m before rest.

Step-by-step explanation:

`a=(F)/(m) =(12N)/(20kg)`

a=0.6 m/s²

`Vf=0=Vi-a.t`

`t=(Vi)/(a) =t=(4.5m/s)/(0.6 m/s2) =t=7.5seg`

`d= Vi.t - (a.t^(2))/(2)`

`d= 4.5 * 7.5 - (0.6*7.5^(2) )/(2) \\\\d=16.875m`