Question

Solve the equation, 3x^2+5x+2=0 using the quadratic formula

Answer 1

Given a quadratic equation
`ax^2+bx+c=0`, the two solution (if they exist) are given by the formula

`x_(1,2)=(-b\pm√(b^2-4ac))/(2a)`

In your case, the coefficients are

`a=3,\quad b=5,\quad c=2`

So the quadratic formula becomes

`x_(1,2)=(-5\pm√(25-24))/(6) = (-5\pm 1)/(6)`

So, the two solutions are

`x_1 = (-5+1)/(6)=-(4)/(6)=-(2)/(3)`

`x_2 = (-5-1)/(6)=-(6)/(6)=-1`