A force of 7.50N is applied to a spring whose spring constant is 0.289 N/cm. Find its change in length.

Question

asked Jun 14, 2020 77.3k views

1 Answer

Dan Lincan · Answer 1 · 2020-06-19T20:17:42+0000

Hook's law states that

$F=k\Delta x$

where F is the applied force, k is the spring constant, and
$\Delta x$ is the change in length.

Plugging your values, we have

$7.5 = 0.289\Delta x \implies \Delta x = (7.5)/(0.289)\approx 25.95$