Question

Describe the nature of the roots for this equation.
3x^2+x-5= 0

Answer 1

This equation has no natural roots.

Explanation:

`3x^2+x-5=0\\\\\text{Use the quadratic formula for}\ ax^2+bx+c=0\\\\x=(-b\pm√(b^2-4ac))/(2a)\\\\\text{For the given equation:}\\\\a=3,\ b=1,\ c=-5\\\\b^2-4ac=1^2-4(3)(-5)=1+60=61\\\\x=(-1\pm√(61))/((2)(3))=(-1\pm√(61))/(6)\\otin\mathbb{N}`

Answer 2

two real,irrational roots.

GOOD LUCK!

Explanation: