Question

A pole vaulter takes 1.3 seconds to fall from peak height to the landing mat. What is his vertical velocity at contact with the mat?

Answer 1

`12.75 (m)/(s)`

Assuming vertical acceleration of
`9.81 (m)/(s^2)`, the speed after x seconds of falling is
`9.81x \to 9.81(1.3) = 12.75`