Question

A proton in a certain particle accelerator has a kinetic energy that is equal to its rest energy. What is the TOTAL energy of the proton as measured by a physicist working with the accelerator? (c = 3.00 × 108 m/s, mproton = 1.67 × 10-27 kg)

Answer 1

Total energy,
`TE=3.006* 10^(-10)\ J`

Step-by-step explanation:

It is given that, a proton in a certain particle accelerator has a kinetic energy that is equal to its rest energy. Let KE is the kinetic energy of the proton and E₀ is its rest energy. So,

`KE=E_o`

The total energy of the proton is equal to the sun of kinetic energy and the rest mass energy.

`TE=KE+E_o`

`TE=2E_o`

`TE=2m_(proton)c^2`

`TE=2* 1.67* 10^(-27)\ kg* (3* 10^8\ m/s)^2`

`TE=3.006* 10^(-10)\ J`

So, the total energy of the proton as measured by a physicist working with the accelerator is
`3.006* 10^(-10)\ J`