Question

The circle below is centered at the point (4, -3) and has a radius of length 3.

What is its equation?
А. (x-3)2 + (y+ 4)2 = 9
В. (x-3)2 + (у- 4)2 = 9
с. (х+4)2 + (у - 3)2 =
22
D. (x-4)2 + (y+ 3)2 =
32

Answer 1

The equation of a circle is written as (x-h)^2 + (y-k)^2 = r^2

where h and k is the center point and r is the radius.

Using the center point and radius given the equation becomes:

(x-4)^2 + (y+3)^2 = 3^2 or (x-4)^2 + (y+3)^2 = 9