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4 votes
Graph the line with slope -2/3 passing through the point (-3,5)​

1 Answer

5 votes

Answer:


\large\boxed{y-5=-(2)/(3)(x+3)}

Explanation:

The point-slope form of an equation of a line:


y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point on a line

We have the slope
m=-(2)/(3) and the point
(-3,\ 5).

Substitute:


y-5=-(2)/(3)(x-(-3))\\\\y-5=-(2)/(3)(x+3)

answered
User TheBigBadBoy
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