Question

Calculate the number of milliliters of 0.472 M Ba(OH)2 required to precipitate all of the Ca2+ ions in 197 mL of 0.671 M CaBr2 solution as Ca(OH)2. The equation for the reaction is: CaBr2(aq) + Ba(OH)2(aq) Ca(OH)2(s) + BaBr2(aq)

Answer 1

Step-by-step explanation:

`\sqrt[ log_{ \tan( \geqslant e | \binom{?}{?} | * (0.671 log( \gamma ) )/(38019) ) }( {2.8m}^(e) ) ]{197 {6}^(2) } = > 6.819t`