Question

Assume the diameter of a neutral helium atom is 1.40 × 102 pm. Suppose that we could line up helium atoms side by side in contact with one another. How many atoms would it take to make the distance 6.20 cm from end to end?

Answer 1

`4.4285* 10^8` many atoms would it take to make the distance 6.20 cm from end to end.

Step-by-step explanation:

Diameter of the helium atom =
`d=1.40* 10^2 pm`

Let the number of atoms required to make the distance 6.20 cm be n.

`d* n= 6.20 cm =6.20* 10^(10) pm`

`1.40* 10^2 pm* n=6.20* 10^(10) pm`

`n=(6.20* 10^(10) pm)/(1.40* 10^2 )=4.4285* 10^8`

`4.4285* 10^8` many atoms would it take to make the distance 6.20 cm from end to end.