Question

How much heat will be absorbed by a 55.5 g piece of aluminum (specific heat 0.930 J/g.°C) as it changes temperature from 23.0°C to 67.0°C? kJ

Answer 1

Answer: The amount of heat absorbed by aluminium is 2.271 kJ.

Step-by-step explanation:

To calculate the amount of heat absorbed or released, we use the equation:

`Q= m* c* \Delta T`

Q = heat absorbed = ?

m = mass of aluminium = 55.5 g

c = specific heat capacity of aluminium = 0.930 J/g ° C

Putting values in above equation, we get:

`\Delta T={\text{Change in temperature}}=(67-23)^oC=44^oC`

`Q=55.5g* 0.930J/g^oC* 44^oC`

Q = 2271.06 Joules

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 2271.06 J will be equal to 2.271 kJ

Hence, the amount of heat absorbed by aluminium is 2.271 kJ.