Question

Rewrite square root of -49 -4 in complex number notation please help

Answer 1

Note that if
`i^2=-1` than
`i=√(-1)`,

Also note that
`√(ab)=√(a)√(b)`

So we have,

`√(-49)=√(-1)√(49)=\boxed{7i}`

and,

`√(-4)=√(-1)√(4)=\boxed{2i}`

Hope this helps.

r3t40