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A coil of self- induction 0.5 H, its ohmic resistance is 10 ⦠carrying a dc current of intensity 2 A, The voltage at its terminals isâ¦â¦ A. Zero

B. 20
C. 5
D. 0.2

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User Adaeze
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1 Answer

4 votes

Answer:

Option (B)

Step-by-step explanation:

L = 0.5 H, I = 2 A, R = 10 Ohm

V = I R

In case of dc the inductor cannot works.

V = 2 x 10 = 20 V

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User Cstrat
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7.8k points