Question

An electrical power plant with an efficiency of 35% rejects 50 MW of heat to the surroundings. What is the flux of heat input to the cycle, in MW? What is the net rate of work (power) generated, in MW? a. b.

Answer 1

a. 76.92 MW

b. 26.92 MW

Step-by-step explanation:

η = Efficiency of the power plant = 0.35

Q₂ = rate at which heat rejected to surrounding = 50 MW

Q₁ = Rate of Input heat = ?

Efficiency of the power plant is given as

`\eta =1-(Q_(2))/(Q_(1))`

`0.35 =1-(50)/(Q_(1))`

Q₁ = 76.92 MW

Net Rate of work is given as

Q = Q₁ - Q₂

Q = 76.92 - 50

Q = 26.92 MW