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A juggler tosses balls vertically to height H. To what height must they be tossed if they are to spend twice as much time in the air?

1 Answer

1 vote

Answer:

The ball must be tossed to a height of 4 times the initial height H

Step-by-step explanation:

We have equation of motion S = ut + 0.5at²

A juggler tosses balls vertically to height H.

That is

H = 0 x t + 0.5 x a x t²

H = 0.5at²

To what height must they be tossed if they are to spend twice as much time in the air.

H' = 0 x 2t + 0.5 x a x (2t)²

H' = 2at² = 4 H

So the ball must be tossed to a height of 4 times the initial height H

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User ZanattMan
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