asked 206k views
4 votes
A ball is released at a height of 27 inches to roll inside a half-cylinder. It rolls

to a height of 9 inches on the other side of the cylinder on roll 1. Each time it
rolls up a side of the cylinder, the ball reaches a point th
high as it
had reached on the other side.
This explicit formula models the height of the ball, in inches, the nth time it
rolls up a side of the cylinder.
How high does the ball roll on its 4th time up the cylinder's side?

A ball is released at a height of 27 inches to roll inside a half-cylinder. It rolls-example-1

2 Answers

2 votes

Answer:

1/3

Explanation:

answered
User ItsLydt
by
7.3k points
3 votes

Answer:


(1)/(3)\ in

Explanation:

we have


a(n)=9((1)/(3))^(n-1)

For n=4

substitute


a(4)=9((1)/(3))^(4-1)


a(4)=9((1)/(3))^(3)


a(4)=9((1)/(27))


a(4)=(1)/(3)\ in

answered
User Rjmoggach
by
7.4k points

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