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The Ransin Sports Company has noted that the size of individual customer orders is normally distributed with a mean of $112 and a standard deviation of $9. If a soccer team of 11 players were to make the next batch of orders, what would be the standard error of the mean? 1.64 0.82 2.71 3.67

asked
User NoelProf
by
8.4k points

1 Answer

0 votes

Answer: 2.71

Explanation:

We know that the formula to calculate the standard error is given by :-


S.E.=(\sigma)/(√(n)), where
\sigma is the standard deviation and 'n' is the sample size.

Given : Standard deviation :
\sigma=\$9

Sample size :
n=11

Then , the standard error of the mean is given by :-


S.E.=(9)/(√(11))=2.7136021012\approx2.71

Hence, the standard error of the mean = 2.71

answered
User MJM
by
8.2k points
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