Question

On a coordinate plane, point AS

located at(74) and point Bis
located at 8.41 What is the
distance between the two points?

Answer 1

√1370 or about 37.01

Explanation:

use distance formula

√(x2-x1)^2+(y2-y1)^2

sqrt(8-7)^2+(41-4)^2

sqrt(1)^2+(37)^2

sqrt 1+1369

sqrt 1370

= about 37. 01