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A cone has a diameter of 12 and a height of 7 what is the area

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\bf \textit{surface area of a cone}\\\\ SA=\pi r√(r^2+h^2)+\pi r^2~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} \stackrel{\textit{half of diameter}}{r=6~\hfill }\\ h=7 \end{cases}\implies SA=\pi (6)√(6^2+7^2)+\pi 6^2 \\\\\\ SA=6\pi √(85)+36\pi \implies SA=6\pi (√(85)+6)\implies SA\approx 286.88

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