Question

What substitution Should be used to re-write 26(x^3+1)^2-22(x^3+1)-3=0 as a quadratic function?

Answer 1

`x^3+1`

Explanation:

`26(x^3+1)^2-22(x^3+1)-3=0`

Comparing to

`A(u)^2+B(u)+C =0`

Where A,B,C are constants

You should see that we need to substitute the
`x^3+1` with u.