Question

Suppose that a monkey is seated at a computer keyboard and randomly strikes the 26 letter keys and the space bar. Find the probability that its first 39 characters (including spaces) will be "to be or not to be that is the question." (Leave your answer as a formula.)

Answer 1

`|\Omega|=27^(39)\\|A|=1\\\\P(A)=(1)/(27^(39))`

In case you want it as a fraction

`P(A)=(1)/(66555937033867822607895549241096482953017615834735226163)`

:D