Question

How much time would a force of 646 N need to stop a 82 kg object moving at 41 m/s (1 decimal place and no spaces between answer and units).

Answer 1

The time is 5.21 s.

Step-by-step explanation:

Given that,

Force F = 646 N

Mass m = 82 kg

Velocity v = 41 m/s

We need to calculate the acceleration

Using formula of force

F= ma

`a = (F)/(m)`

`a = (646)/(82)`

`a =7.87\ m/s^2`

We need to calculate the time

Now, using equation of motion

`v = u+at`

`41=0+7.87 t`

`t = (41)/(7.87)`

`t = 5.21\ s`

Hence, The time is 5.21 s.