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The product of (3+2i) and a complex number is (17+7i)

The product of (3+2i) and a complex number is (17+7i)
asked 135k views
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The product of (3+2i) and a complex number is (17+7i)

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User Christopher Lawless
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1 Answer

4 votes

Answer:


\large\boxed{(3+2i)(17+7i)=37+55i}

Explanation:


\text{Use}\ \bold{FOIL}\ (a+b)(c+d)=ac+ad+bc+bd,\ \text{and}\ i^2=-1:\\\\(3+2i)(17+7i)\\\\=(3)(17)+(3)(7i)+(2i)(17)+(2i)(7i)\\\\=51+21i+34i+14i^2\\\\=51+21i+34i+14(-1)\\\\=51+21i+34i-14\qquad\text{combine like terms}\\\\=(51-14)+(21i+34i)\\\\=37+55i

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User Evmorov
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