Question

The sum of 5 consecutive even numbers is 310.
What is the third number in this sequence?

Answer 1

2,2n+2,2n+4,2n+6,2n+8 - 5 consecutive even integers

2n+4 - 3rd number

`2n+2n+2+2n+4+2n+6+2n+8=310\\10n+20=310\\10n=290\\n=29\\\\2n+4=2\cdot29+4=62`

Answer 2

Answer:62

Explanation:

The differance between 2 consecutive even number is 2...so if the first consecutive even number is x, then the next 4 consecutive even number will(x+2),(x+4),(x+6),(x+8)

So

X+(x+2)+(x+4)+(x+6)+(x+8)=310

5x+20=310

So,x=58

As the third number is (x+4)

Putting the value of x the final result comes(58+4)=62.