A water main is to be constructed with a 12.512.5% grade in the north direction and a 2020% grade in the east direction. Determine the angle thetaθ required in the water main …

Question

asked Sep 3, 2020 56.7k views

1 Answer

Pazulx · Answer 1 · 2020-09-10T18:01:12+0000

Answer:

The angle required in the water is 32°.

Step-by-step explanation:

Given that,

Grade in the north = 12.5 %

Grade in the east = 20 %

We need to calculate the angle

We know that,

$tan\theta=(North)/(East)$

$tan\theta=(12.5)/(20)$

$tan\theta=0.625$

$\theta=tan^(-1)0.625$

$\theta=32^(\circ)$

Hence, The angle required in the water is 32°.