Question

A 66.2 kg ice skater moving to the right with a velocity of 2.47 m/s throws a 0.136 kg snowball to the right with a velocity of 31.4 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.

Answer 1

v = 2.41 m/s

Step-by-step explanation:

Here net force on the Skater + snowball is zero

so here we can use momentum conservation for skater + snowball

`m_1v_(1i) + m_2v_(2i) = m_1v_(1f) + m_2v_(2f)`

now we have

`66.2(2.47) + (0.136)(2.47) = 66.2 (v) + 0.136(31.4)`

`163.85 = 66.2 v + 4.27`

`163.85 - 4.27 = 66.2 v`

`v = (159.6)/(66.2)`

`v = 2.41 m/s`

so the final speed of skater will be 2.41 m/s