Question

Find the equation of the circle whose center and radius are given.
center (0,8), radius = 8​

Answer 1

Answer: x² +( y - 8 )² =64

Step-by-step explanation: happy to help :)

Answer 2

`x^2 +(y-8)^2=64`

Explanation:

The equation of the circle with center at point
`(x_0,y_0)` and radius r is

`(x-x_0)^2+(y-y_0)^2=r^2`

In your case,

• 
  `x_0=0`
• 
  `y_0=8`
• 
  `r=8`

So, the equation of the circle with center at (0,8) and radius r=8 is

`(x-0)^2+(y-8)^2=8^2\\ \\x^2 +(y-8)^2=64`