Question

Help! What is the equation on the graph. I have tried x^2+1 and it marks it incorrect

Answer 1

`y=2x^(2)+1`

Explanation:

we know that

The graph is a vertical parabola open upward

The vertex is the point (0,1)

The equation of a vertical parabola in vertex form is equal to

`y=a(x-h)^(2)+k`

substitute the vertex in the equation

`y=a(x-0)^(2)+1`

`y=a(x)^(2)+1`

Find the value of coefficient a

Observing the graph

For x=1, y=3

substitute in the equation

`3=a(1)^(2)+1`

`a=3-1=2`

The equation on the graph is equal to

`y=2x^(2)+1`