Question

PHYSICS PLEASE HELP

a. Draw a force diagram

b. The skier has a mass of 76.6 kg and the coefficient of kinetic friction between the skier and the snow is 0.15. The angle the hill makes to the horizontal is 38 degrees and the distance the skier glides down the hill is 40.5 m. Answer the following questions based on this information.

What is the magnitude of the normal force on the skier as they glide down the hill? Show your work.

c. What is the magnitude of the force of friction on the skier as they glide down the hill? Show your work.

d. What is the acceleration of the skier as they glide down the hill? Show your work.

e. What is the speed of the skier when they reach the end of the straight section of the hill? Show your work.

f. How many seconds does the skier take to reach the end of the straight section of the hill? Show your work.

Answer 1

Step-by-step explanation:

b )

Normal force R = mgcosθ

= 76.6 x 9.8 x cos 38

R = 591.5 N

c )

Force of friction

= μ R

μ is coefficient of friction .

= .15 x 591.5

= 88.73 N

d )

Net force

= mg sinθ - friction

= 76.6 x 9.8 x sin 38 - 88.73

= 462.16 - 88.73

= 373.43 N

Acceleration = 373.43 / 76.6

a = 4.87 m / s²

e )

v² = u² + 2 a s

s = 40.5 m

a = 4.87

u = 0

v² = 0 +2 x 4.87 x 40.5

= 394.5

v = 19.86 m /s

f )

v = u + a t

19.86 = 0 + 4.87 t

t = 4 .07 s