Question

I need help please!

Answer 1

0.0466

Explanation:

For a random variable X which follows a binomial distribution:

`n = 7\\p = 0.35`

Thus,

`P(X=5)={7\choose5}(0.35)^5(1-0.35)^(7-5)\\P(X=5)={7\choose5}(0.35)^5(0.65)^(2)\\P(X=5)=0.0466`