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What is the lcm of xy(x+1) and x(x+2)

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xy(x+1)=x\cdot y\cdot (x+1)\\x(x+2)=x\cdot (x+2)\\\\\text{lcm}(xy(x+1),x(x+2))=x\cdot y \cdot (x+1)\cdot (x+2)=xy(x+1)(x+2)

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User Pavlo Dyban
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