Question

The specific heat of copper is 385 J/kg·K. If a 2.6 kg block of copper is heated from 340 K to 450 K, how much thermal energy is absorbed?

Answer 1

Answer: 110,110J or 110kJ

Q=mc*change in temp

Q=(2.6kg)(385J/kg*K)(450K-340K)=110,110J

Q=110kJ

Answer 2

Heat absorbed, Q = 110110 J

Step-by-step explanation:

It is given that,

The specific heat of copper is,
`c=385\ J/kg.K`

Mass of block, m = 2.6 kg

Initial temperature,
`T_1=340\ K`

Final temperature,
`T_2=450\ K`

Thermal energy is given by :

`Q=mc\Delta T`

`Q=mc(T_2-T_1)`

`Q=2.6* 385* (450-340)`

Q = 110110 J

So, the thermal heat of 110110 J is absorbed. Hence, this is the required solution.