Question

prove that the line whose intercepts on the axes of x and y. are respectively -2and3 pass Through the point 2 and 6​

Answer 1

see explanation

Explanation:

Using the intercept form of the equation of a straight line

`(x)/(a)` +
`(y)/(b)` = 1

where a is the x- intercept and b the y- intercept

here a = - 2 and b = 3, hence

`(x)/(-2)` +
`(y)/(3)` = 1

Multiply through by - 6

3x - 2y = - 6 ← equation in standard form

Substitute x = 2 and y = 6 into the left side of the equation and if equal to the right side then (2, 6) lies on the line

left side = (3 × 2) - 2(6) = 6 - 12 = - 6

Hence line passes through (2, 6)