Question

Find the number of real number solutions for the equation. x2 + 5x + 7 = 0 0 cannot be determined 1 2

Answer 1

`\Delta=5^2-4\cdot1\cdot7=25-28=-3`

`\Delta<0` so 0 solutions.

Answer 2

No Real roots to this Quadratic Equation

Explanation:

Our Quadratic equation is given as

`x^2+5x+7=0`

In order to find that do we have the real roots of a quadratic equation , the Discriminant must be greater or equal to 0. The Discriminant is denoted by D and given by the formula

`D= b^2-4ac`

Where b is the coefficient of the middle term containing x, a is the coefficient of the term containing
`x^(2)` and the c is the constant term.

Hence we have

a = 1 , b = 5 and c = 7

Calculate D

`D=b^2-4ac\\D=5^2-4*1*7\\D=25-28\\D=-3`

Hence we see that the Discriminant (D) is less than 0, our answer is no real roots to this quadratic equation.