Question

Given the equation y − 4 = three fourths(x + 8) in point-slope form, identify the equation of the same line in standard form.

−three fourthsx + y = 10
3x − 4y = −40
y = three fourthsx + 12
y = three fourthsx + 10

Answer 1

`3x-4y=-40`

Explanation:

The standard form of a linear equation is
`ax+by=c`.

The given line has equation:

`y-4=(3)/(4)(x+8)`

This is the point-slope form of the given line.

To find the standard form, we clear the fraction

`4y-16=3(x+8)`

We expand the parenthesis now to get:

`4y-16=3x+24`

We group the variables on the LHS and the constants on the RHS.

`4y-3x=24+16`

`-3x+4y=40`

Multiply through by -1

`3x-4y=-40`

This is of the form:
`ax+by=c`.