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A fair die is cast four times. Calculate the probability of obtaining exactly two 6's round to the nearest tenth of a percent

A fair die is cast four times. Calculate the probability of obtaining exactly two 6's round to the nearest tenth of a percent
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a fair die is cast four times. Calculate the probability of obtaining exactly two 6's round to the nearest tenth of a percent

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User Richard Poirier
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|\Omega|=6^4=1296\\|A|=1\cdot1\cdot5\cdot5\cdot(4!)/(2!2!)=25\cdot6=150\\\\P(A)=(150)/(1296)\approx11.6\%

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User Peter Tsung
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