Question

What is the magnitude of the acceleration vector which causes a particle to move from velocity −5i−2j m/s to −6i+ 7j m/s in 8 seconds. Answer in m/s.

Answer 1

Acceleration,
`a=(1)/(8)(-i+9j)\ m/s^2`

Step-by-step explanation:

Initial velocity of a particle in vector form, u = (-5i - 2j) m/s

Final velocity of particle in vector form, v = (-6i + 7j) m/s

Time taken, t = 8 seconds

We need to find the magnitude of acceleration vector. The changing of velocity w.r.t time is called acceleration of a particle. It is given by :

`a=(v-u)/(t)`

`a=((-6i+7j)\ m/s-(-5i-2j)\ m/s)/(8\ s)`

`a=((-i+9j))/(8\ s)\ m/s^2`

or

`a=(1)/(8)(-i+9j)\ m/s^2`

Hence, the value of acceleration vector is solved.