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Find the equation in standard form , of the line passing through points (2,-3) and (4,2)

asked
User JoeB
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8.2k points

1 Answer

5 votes

The form of linear equation that describes line is:


y=sx+n

First we must calculate the slope.


s=\frac{\Delta{y}}{\Delta{x}}=(2-(-3))/(4-2)=(5)/(2)

Now it looks a bit more like this:


y=(5)/(2)x+n

All we need now is to put in y and x from one point doesn't matter which. I'll pick A.

The equation now looks like this:


-3=(5)/(2)\cdot2+n

Solve for n.


</p><p>-3=5+n \\</p><p>n=-8</p><p>

And finally write the equation.


f(x)=(5)/(2)x-8

Hope this helps.

r3t40

answered
User Ramesh Akula
by
8.0k points

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