asked 80.4k views
3 votes
Factor 200t+8t^3-80t^2

2 Answers

6 votes

Answer:

8t(t - 5)^2

Explanation:

I would immediately rearrange these terms in descending order by powers of t:

8t^3 - 80t^2 + 200t

Then I'd factor out 8t:

8t(t^2 - 10 t + 25).

Finally, I'd factor the quadratic t^2 - 10 t + 25:

(t - 5)^2

and so 200t+8t^3-80t^2 in factored form is 8t(t - 5)^2.

answered
User Vaulstein
by
8.4k points
4 votes

Answer:

Explanation:

It would be better to list the terms in descending order.

8t^3 - 80t^2 + 200t Take out a common factor of t

t(8t^2 - 80t + 200) Now take out 8

8t (t^2 - 10t + 25) Now factor the polynomial

8t(t - 5)(t - 5)

answered
User Jonio
by
9.0k points

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