Question

Given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form.

Answer 1

x-2y = -12

Explanation:

Standard form of a line is in the form Ax + By = C where A is a positive integer

y − 3 = 1/2(x + 6)

Multiply each side by 2 to eliminate the fractions

2(y-3)= 1/2*2 (x+6)

Distribute

2y -6 = x+6

Subtract x from each side

-x +2y -6 = x-x +6

-x+2y -6 = 6

Add 6 to each side

-x+ 2y -6+6 = 6+6

-x +2y = 12

Multiply each side by -1 to make A a positive integer

x-2y = -12