Question

A specific park is rectangular-shaped and has a 3 mile-perimeter. The length is 4 times the width. What are the dimensions of the park?​

Answer 1

The length of the rectangular park is
`1.2\ mi` and the width of the rectangular park is
`0.3\ mi`

Explanation:

Let

x ----> the length of the rectangular park

y ---> the width of the rectangular park

we know that

The perimeter is equal to

`P=2(x+y)`

`P=3\ mi`

so

`3=2(x+y)` -----> equation A

`x=4y` ----> equation B

substitute equation B in equation A and solve for y

`3=2(4y+y)`

`3=10y`

`y=0.3\ mi`

Find the value of x

`x=4(0.3)=1.2\ mi`

therefore

The length of the rectangular park is
`1.2\ mi` and the width of the rectangular park is
`0.3\ mi`