Question

(01.03)

Solve the equation for x.

the square root of the quantity x plus 5 end quantity minus 3 equals 4

Answer 1

x=1 if I understood correctly.

Explanation:

`√(x) + 5 + x - 3 = 4`

`√(x) + 2 + x = 4`

`√(x) + x = 2`

At this point if you try all the integers, you will find that only 1 is the solution to this equation, because:

`√(1) + 1 = 2`

`1 + 1 = 2`

`2 = 2`

Hope I helped!

Answer 2

For this case we must solve the following equation:

`\sqrt {x + 5} -3 = 4`

We add 3 to both sides of the equation:

`\sqrt {x + 5} = 4 + 3\\\sqrt {x + 5} = 7`

We raise the square to eliminate the root:

`x + 5 = 7 ^ 2\\x + 5 = 49`

We subtract 5 on both sides of the equation:

`x = 49-5\\x = 44`

Answer:

`x = 44`