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What is the equation of the parabola with focus (1,1/2) and directrix y=3 Answers: A. Y=-1/5x^2+2/5x+31/20 B. Y=-3/16x^2 C. Y=-3/5x^2-14/31x+71/16 D. Y=-x^2+17x-1

What is the equation of the parabola with focus (1,1/2) and directrix y=3 Answers: A. Y=-1/5x^2+2/5x+31/20 B. Y=-3/16x^2 C. Y=-3/5x^2-14/31x+71/16 D. Y=-x^2+17x-1
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What is the equation of the parabola with focus (1,1/2) and directrix y=3

Answers:
A. Y=-1/5x^2+2/5x+31/20
B. Y=-3/16x^2
C. Y=-3/5x^2-14/31x+71/16
D. Y=-x^2+17x-1

What is the equation of the parabola with focus (1,1/2) and directrix y=3 Answers-example-1
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User ReedD
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Answer: A


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User Colin Dabritz
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