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!!!!!!PLEASE HELP!!!!!What is the minimum value for the function f(x)=1/2(x+3)(x-5)

1 Answer

3 votes

Answer:

the minimum value is 1/2x^2+4x+15/2 (write down the work below)

Explanation:

f(x)=1/2*(x+3)*(x+5)=0

multiply the parenthesis by 1/2

(1/2x+3/2)*(x+5)

multiply the parenthesis

1/2x^2+5/2x+3/2x+15/2

calculate the equation

1/2x^2+4x+15/2 is you're answer

answered
User Remco Beugels
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